问题 解答题
(1)(
x+2
x2-2x
-
x-1
x2-4x+4
)÷
4-x
x

(2)1-(a-
1
1-a
a2-a+1
a2-2a+1
答案

(1)(

x+2
x2-2x
-
x-1
x2-4x+4
)÷
4-x
x

=(

x+2
x(x-2)
-
x-1
(x-2)2
)×
x
4-x

=[

(x+2)(x-2)
x(x-2)2
-
x(x-1)
x(x-2)2
x
4-x

=

x-4
x(x-2)2
×
x
4-x

=-

1
(x-2)2

(2)1-(a-

1
1-a
a2-a+1
a2-2a+1

=1-

a(1-a)-1
1-a
×
(a-1)2
a2-a+1

=1+(1-a)

=2-a.

问答题
单项选择题