问题
解答题
先化简,再求值:(a-
|
答案
原式=[
-a(a+1) a+1
]÷2a a+1
-a2(a-1)2 (a+1)(a-1)
=
•a(a-1) a+1
-a2(a+1)(a-1) (a-1)2
=a-a2,
∵a是方程2x2-2x-9=0的解,
∴将x=a代入方程得:2a2-2a-9=0,
∴a2-a=
,即a-a2=-9 2
,9 2
则原式=-
.9 2
先化简,再求值:(a-
|
原式=[
-a(a+1) a+1
]÷2a a+1
-a2(a-1)2 (a+1)(a-1)
=
•a(a-1) a+1
-a2(a+1)(a-1) (a-1)2
=a-a2,
∵a是方程2x2-2x-9=0的解,
∴将x=a代入方程得:2a2-2a-9=0,
∴a2-a=
,即a-a2=-9 2
,9 2
则原式=-
.9 2