问题
解答题
化简
|
答案
原式=
×x-2 (x+1)(x-1)
+(x+1)2 2(x+1) 1 x-1
=
+x-2 2(x+1) 1 x-1
=
+x-2 2(x-1) 2 2(x-1)
=
，x 2(x-1)
当x=2时，原式=
=1．2 2×(2-1)
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化简
|
原式=
×x-2 (x+1)(x-1)
+(x+1)2 2(x+1) 1 x-1
=
+x-2 2(x+1) 1 x-1
=
+x-2 2(x-1) 2 2(x-1)
=
，x 2(x-1)
当x=2时，原式=
=1．2 2×(2-1)