问题 解答题
先化简,再求值:(
1
x-y
-
1
x+y
2y
x2+2xy+y2
,其中x=
3
+
2
y=
3
-
2
答案

(

1
x-y
-
1
x+y
2y
x2+2xy+y2
=
(x+y)-(x-y)
(x-y)(x+y)
(x+y)2
2y

=

2y
(x-y)(x+y)
(x+y)2
2y
=
x+y
x-y

x=

3
+
2
y=
3
-
2
代入上式,得

原式=

(
3
+
2
)+(
3
-
2
)
(
3
+
2
)-(
3
-
2
)
=
2
3
2
2
=
6
2

单项选择题
单项选择题