问题
解答题
先化简,再求值:
|
答案
原式=
•xy-y2-x2-xy (x-y)(x+y) x+y x2+y2
=-
•y2+x2 (x-y)(x+y) x+y x2+y2
=-
,1 x-y
将x=2,y=-1代入=-
,1 x-y
原式=-
=-1 2+1
.1 3
先化简,再求值:
|
原式=
•xy-y2-x2-xy (x-y)(x+y) x+y x2+y2
=-
•y2+x2 (x-y)(x+y) x+y x2+y2
=-
,1 x-y
将x=2,y=-1代入=-
,1 x-y
原式=-
=-1 2+1
.1 3