先化简,再求值:(
|
原式=[
-(a-2)(a+2) (a-2)2
]•1 a-2 a(a-2) 2
=[
-a+2 a-2
]•1 a-2 a(a-2) 2
=
•a+1 a-2 a(a-2) 2
=
,a2+a 2
当a2+a=5时,原式=
.5 2
先化简,再求值:(
|
原式=[
-(a-2)(a+2) (a-2)2
]•1 a-2 a(a-2) 2
=[
-a+2 a-2
]•1 a-2 a(a-2) 2
=
•a+1 a-2 a(a-2) 2
=
,a2+a 2
当a2+a=5时,原式=
.5 2