问题
解答题
计算: (1)
(2)(-
(3)
(4)
|
答案
(1)原式=18x4y-3×
xy-3=1 12
;3x5 2y6
(2)原式=
•(-a4 b2
)÷(b6 8a3
)1 a12b8
=-
a13b12;1 8
(3)原式=
-4 a+2
=(a+2)2 a+2
=4-(a+2)2 a+2
=--a2-4a a+2
;a2+4a a+2
(4)原式=
÷3-x x-2 (x+2)(x-2)-5 x-2
=
÷3-x x-2 (x+3)(x-3) x-2
=
•3-x x-2 x-2 (x+3)(x-3)
=-
.1 x+3