问题
解答题
先化简,再求值:
|
答案
原式=
+x-4 x-2
×x-4 (x-2)^2
,x-2 x
=
+x-4 x-2
,4 x(x-2)
=
+x(x-4) x(x-2)
,4 x(x-2)
=
,(x-2)2 x(x-2)
=
;(x-2) x
当x=
时,原式=2
=1-
-22 2
.2
先化简,再求值:
|
原式=
+x-4 x-2
×x-4 (x-2)^2
,x-2 x
=
+x-4 x-2
,4 x(x-2)
=
+x(x-4) x(x-2)
,4 x(x-2)
=
,(x-2)2 x(x-2)
=
;(x-2) x
当x=
时,原式=2
=1-
-22 2
.2