问题 填空题

当a=-2时,(b-a)(a+b)(a2+b2)-(a4+b4)的值为______.

答案

(b-a)(a+b)(a2+b2)-(a4+b4

=(b2-a2)(a2+b2)-(a4+b4

=(b4-a4)-(a4+b4

=-2a4

∵a=-2,

∴原式=-2×a4=-2×(-2)4=-32.

故答案为:-32.

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