问题
解答题
(1)计算:(3-
(2)先化简,再求值:(
|
答案
(1)原式=9-6
+2-12
=10-6
; 2
(2)原式=
×4 (a+2)(a-2) 2-a 2
=
×2 a+2 -1 1
=-
,2 a+2
当a=
-1时,原式=-3
=-2 a+2
=1-2
-1+23
.3
(1)计算:(3-
(2)先化简,再求值:(
|
(1)原式=9-6
+2-12
=10-6
; 2
(2)原式=
×4 (a+2)(a-2) 2-a 2
=
×2 a+2 -1 1
=-
,2 a+2
当a=
-1时,原式=-3
=-2 a+2
=1-2
-1+23
.3