问题
解答题
先化简,再求值:
|
答案
÷9-x2 x2+4x+4
•x-3 2x+4 x-1 x+3
=
×(3+x)(3-x) (x+2)2
×2(x+2) x-3 x-1 x+3
=-
;2(x-1) x+2
∵x=tan60°-4cos60°=
-4×3
=1 2
-2,3
∴原式=-
)2(
-2-1)3
-2+23
=-(2-2
)3
=2
-2.3
先化简,再求值:
|
÷9-x2 x2+4x+4
•x-3 2x+4 x-1 x+3
=
×(3+x)(3-x) (x+2)2
×2(x+2) x-3 x-1 x+3
=-
;2(x-1) x+2
∵x=tan60°-4cos60°=
-4×3
=1 2
-2,3
∴原式=-
)2(
-2-1)3
-2+23
=-(2-2
)3
=2
-2.3