问题
解答题
计算.1-(1-
|
答案
原式=1-(
)2•1-x-1 1-x (x-1)2 x2-x+1
=1-(
)2•-x 1-x (1-x)2 x2-x+1
=1-x2-x+1-x2 x2-x+1
=
.-x+1 x2-x+1
计算.1-(1-
|
原式=1-(
)2•1-x-1 1-x (x-1)2 x2-x+1
=1-(
)2•-x 1-x (1-x)2 x2-x+1
=1-x2-x+1-x2 x2-x+1
=
.-x+1 x2-x+1