问题
解答题
计算:(1)
(2)先化简,再求值
|
答案
(1)原式=
(2×2
-2 2
)+3 2
=2-6 2
+3
;6 2
(2)原式=
×(a+1)(a-1) a+3
=2 a+1
,2(a-1) a+3
又∵a=2tan60°-3=2
-3,3
∴原式=
=2(2
-3-1)3 2
-3+33
=4
-83 2 3
.6-4 3 3
计算:(1)
(2)先化简,再求值
|
(1)原式=
(2×2
-2 2
)+3 2
=2-6 2
+3
;6 2
(2)原式=
×(a+1)(a-1) a+3
=2 a+1
,2(a-1) a+3
又∵a=2tan60°-3=2
-3,3
∴原式=
=2(2
-3-1)3 2
-3+33
=4
-83 2 3
.6-4 3 3