问题
解答题
先化简,再求值:(
|
答案
原式=[
-x+2 x(x-2)
]÷x-1 (x-2)2 x2-16 x2+4x
=[
-x2-4 x(x-2)2
]÷x2-x x(x-2)2 x2-16 x2+4x
=
•x-4 x(x-2)2 x(x+4) (x+4)(x-4)
=
,1 (x-2)2
当x=2+
时,3
原式=1 (2+
-2)23
=
.1 3
先化简,再求值:(
|
原式=[
-x+2 x(x-2)
]÷x-1 (x-2)2 x2-16 x2+4x
=[
-x2-4 x(x-2)2
]÷x2-x x(x-2)2 x2-16 x2+4x
=
•x-4 x(x-2)2 x(x+4) (x+4)(x-4)
=
,1 (x-2)2
当x=2+
时,3
原式=1 (2+
-2)23
=
.1 3