问题 解答题

观察以下等式:

(x+1)(x2-x+1)=x3+1

(x+3)(x2-3x+9)=x3+27

(x+6)(x2-6x+36)=x3+216

(1)按以上等式的规律,填空:(a+b)(______)=a3+b3

(2)利用多项式的乘法法则,证明(1)中的等式成立.

(3)利用(1)中的公式化简:(x+y)(x2-xy+y2)-(x-y)(x2+xy+y2

答案

(1)(a+b)(a2-ab+b2)=a3+b3

(2)(a+b)(a2-ab+b2

=a3-a2b+ab2+a2b-ab2+b3

=a3+b3

(3)(x+y)(x2-xy+y2)-(x-y)(x2+xy+y2

=x3+y3-(x3-y3

=2y3

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