问题
解答题
化简,求值:
|
答案
原式=
÷m2-2m+1 m2-1
,(m-1)(m+1)-(m-1) m+1
=
•(m-1)2 (m-1)(m+1)
,m+1 m2-1-m+1
=
•m-1 m+1
,m+1 m2-m
=
,m-1 m2-m
=
,m-1 m(m-1)
=
.1 m
∴当m=
时,原式=3
=1 3
.3 3
化简,求值:
|
原式=
÷m2-2m+1 m2-1
,(m-1)(m+1)-(m-1) m+1
=
•(m-1)2 (m-1)(m+1)
,m+1 m2-1-m+1
=
•m-1 m+1
,m+1 m2-m
=
,m-1 m2-m
=
,m-1 m(m-1)
=
.1 m
∴当m=
时,原式=3
=1 3
.3 3