问题
解答题
计算：
|
答案
原式=
÷[2x-6 x-2
-(x+2)]5 x-2
=
÷[2(x-3) x-2
-5 x-2
](x+2)(x-2) x-2
=
÷2(x-3) x-2 5-(x2-4) x-2
=
÷2(x-3) x-2 9-x2 x-2
=
•2(x-3) x-2 x-2 (3+x)(3-x)
=2(x-3)•
=-1 -(x+3)(x-3)
．2 x+3
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