问题
解答题
先化简,再求值:
|
答案
原式=
-x2+1 x2-1
•x-2 x-1 x x-2
=
-x2+1 (x+1)(x-1)
(2分)x x-1
=
(4分)x2+1-x(x+1) (x+1)(x-1)
=1-x (x+1)(x-1)
=-
.(6分)1 x+1
∴当x=-3时,原式=-
=1 -3+1
.(8分)1 2
先化简,再求值:
|
原式=
-x2+1 x2-1
•x-2 x-1 x x-2
=
-x2+1 (x+1)(x-1)
(2分)x x-1
=
(4分)x2+1-x(x+1) (x+1)(x-1)
=1-x (x+1)(x-1)
=-
.(6分)1 x+1
∴当x=-3时,原式=-
=1 -3+1
.(8分)1 2