问题
解答题
化简：(
|
答案
原式=[
-3a(a-1) (a+1)(a-1)
]•a(a+1) (a+1)(a-1) (a+1)(a-1) 2a
=
•2a(a-2) (a+1)(a-1) (a+1)(a-1) 2a
=a-2．
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化简：(
|
原式=[
-3a(a-1) (a+1)(a-1)
]•a(a+1) (a+1)(a-1) (a+1)(a-1) 2a
=
•2a(a-2) (a+1)(a-1) (a+1)(a-1) 2a
=a-2．