问题
解答题
已知x=
|
答案
原式=[
-x+1 x(x-1)
]•x=x (x-1)2
-x+1 x-1
(2分)x2 (x-1)2
=
-(x+1)(x-1) (x-1)2
(4分)x2 (x-1)2
=
=x2-1-x2 (x-1)2
(6分)-1 (x-1)2
∴当x=
+1时,原式=3
=--1 (
+1-1)23
.(7分)1 3
已知x=
|
原式=[
-x+1 x(x-1)
]•x=x (x-1)2
-x+1 x-1
(2分)x2 (x-1)2
=
-(x+1)(x-1) (x-1)2
(4分)x2 (x-1)2
=
=x2-1-x2 (x-1)2
(6分)-1 (x-1)2
∴当x=
+1时,原式=3
=--1 (
+1-1)23
.(7分)1 3