问题
填空题
化简：
|
答案
原式=
÷x-y x+3y
-(x+y)(x-y) (x+3y)2 2y x+y
=
×x-y x+3y
-(x+3y)2 (x+y)(x-y) 2y x+y
=
-x+3y x+y 2y x+y
=x+3y-2y x+y
=1．
故答案为：1．
搜题请搜索小程序“爱下问搜题”
化简：
|
原式=
÷x-y x+3y
-(x+y)(x-y) (x+3y)2 2y x+y
=
×x-y x+3y
-(x+3y)2 (x+y)(x-y) 2y x+y
=
-x+3y x+y 2y x+y
=x+3y-2y x+y
=1．
故答案为：1．