问题
解答题
先化简,再求值:(
|
答案
原式=
•(x+1)(x-1)-(x-2)2 (x-2)(x-1)
-(x+2)(x-2) x(4x-5) 1 x-1
=
•4x-5 x-1
-x+2 x(4x-5)
,1 x-1
=
-x+2 x(x-1)
,x x(x-1)
=
,2 x2-x
∵2x2-2x-7=0,
∴x2-x=
,7 2
∴原式=
;4 7
先化简,再求值:(
|
原式=
•(x+1)(x-1)-(x-2)2 (x-2)(x-1)
-(x+2)(x-2) x(4x-5) 1 x-1
=
•4x-5 x-1
-x+2 x(4x-5)
,1 x-1
=
-x+2 x(x-1)
,x x(x-1)
=
,2 x2-x
∵2x2-2x-7=0,
∴x2-x=
,7 2
∴原式=
;4 7