问题
解答题
先化简,再求值:(
|
答案
原式=
•a(a+2)+a(a-1) (a-1)(a+2) a+2 2a2+3a+1
=
•2a2+a (a-1)(a+2) a+2 2a2+3a+1
=
•a(2a+1) (a-1)(a+2) a+2 (a+1)(2a+1)
=
,a a2-1
当a=
=1
-12
+1时,2
原式=
=
+12 2(
+1)2
.1 2
先化简,再求值:(
|
原式=
•a(a+2)+a(a-1) (a-1)(a+2) a+2 2a2+3a+1
=
•2a2+a (a-1)(a+2) a+2 2a2+3a+1
=
•a(2a+1) (a-1)(a+2) a+2 (a+1)(2a+1)
=
,a a2-1
当a=
=1
-12
+1时,2
原式=
=
+12 2(
+1)2
.1 2