问题 解答题
已知x=2+
2
,求(
x+2
x2-2x
-
x
x-2
x-1
x
的值.
答案

原式=[

x+2
x(x-2)
-
x2
x(x-2)
x
x-1

=

x+2-x2
x(x-2)
×
x
x-1

=-

(x+1)(x-2)
x(x-2)
×
x
x-1

=-

x+1
x-1

当x=2+

2
时,

原式=-

x+1
x-1

=-

2+
2
+1
2+
2
-1

=-

2
+3
2
+1

=1-2

2

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