问题
解答题
已知x=2+
|
答案
原式=[
-x+2 x(x-2)
]×x2 x(x-2) x x-1
=
×x+2-x2 x(x-2) x x-1
=-
×(x+1)(x-2) x(x-2) x x-1
=-
,x+1 x-1
当x=2+
时,2
原式=-x+1 x-1
=-2+
+12 2+
-12
=-
+32
+12
=1-2
.2
已知x=2+
|
原式=[
-x+2 x(x-2)
]×x2 x(x-2) x x-1
=
×x+2-x2 x(x-2) x x-1
=-
×(x+1)(x-2) x(x-2) x x-1
=-
,x+1 x-1
当x=2+
时,2
原式=-x+1 x-1
=-2+
+12 2+
-12
=-
+32
+12
=1-2
.2