问题
解答题
计算：(
|
答案
原式=[
-a+2 a(a-2)
]÷a-1 (a-2)2 4-a a(a-2)
=[
-a+2 a(a-2)
]•a-1 (a-2)2 a(a-2) 4-a
=
-a+2 4-a
×a(a-1) a-2 1 4-a
=(a+2)(a-2)-a(a-1) (4-a)(a-2)
=a-4 (4-a)(a-2)
=-a-4 (a-4)(a-2)
=-
．1 a-2
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