问题 解答题
化简求值:(1+
y2
x2-y2
)•
x-y
x
,其中x-3y=0,且y≠0.
答案

原式=(

x2-y2
x2-y2
+
y2
x2-y2
)•
x-y
x

=

x2
x2-y2
x-y
x

=

x2
(x+y)(x-y)
x-y
x

=

x
x+y

由x-3y=0,得x=3y,

∴原式=

3y
3y+y
=
3y
4y
=
3
4

单项选择题
单项选择题