问题
解答题
先化简,再求值
|
答案
原式=
-1 x+1
•x+3 (x+1)(x-1) (x-1)2 (x+1)(x+3)
=
-1 x+1
=x-1 (x+1)2
=x+1-(x-1) (x+1)2 2 (x+1)2
当x=
时,原式=2
=2 (
+1)22
=6-42 2
+32
.2
先化简,再求值
|
原式=
-1 x+1
•x+3 (x+1)(x-1) (x-1)2 (x+1)(x+3)
=
-1 x+1
=x-1 (x+1)2
=x+1-(x-1) (x+1)2 2 (x+1)2
当x=
时,原式=2
=2 (
+1)22
=6-42 2
+32
.2