问题 解答题
(1)解方程:3x2-6x+1=0;
(2)化简求值:
x2-1
x2+2x+1
1
2x-2
,其中x=-
1
2
答案

(1)3x2-6x+1=0.这里a=3,b=-6,c=1.△=b2-4ac=36-12=24>0;

x=

-b±
b2-4ac
2a

=

24
2×3

=

6
3

即x1=

3+
6
3
,x2=
3-
6
3

(2)

x2-1
x2+2x+1
1
2x-2

=

(x+1)(x-1)
(x+1)2
1
2(x-1)

=

1
2(x+1)
(或
1
2x+2
);

当x=-

1
2
时,原式=
1
2(x+1)
=
1
2(-
1
2
+1)
=1

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