问题
解答题
先化简,再求值:
|
答案
原式=
-(x+1)(x-1) (x-1)2
×x(x-2) (x-1)(x-2) 1 x
=
-x+1 x-1 1 x-1
=
,x x-1
当x=
=1
-12
+1时,2
原式=
=1+
+12
+1-12
.2 2
先化简,再求值:
|
原式=
-(x+1)(x-1) (x-1)2
×x(x-2) (x-1)(x-2) 1 x
=
-x+1 x-1 1 x-1
=
,x x-1
当x=
=1
-12
+1时,2
原式=
=1+
+12
+1-12
.2 2