问题 解答题
先化简,再求值:
x2-1
x2-2x+1
-
x2-2x
x2-3x+2
÷x,其中x=
1
2
-1
答案

原式=

(x+1)(x-1)
(x-1)2
-
x(x-2)
(x-1)(x-2)
×
1
x

=

x+1
x-1
-
1
x-1

=

x
x-1

当x=

1
2
-1
=
2
+1
时,

原式=

2
+1
2
+1-1
=1+
2
2

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