问题
填空题
已知3a2-2ab3-7an-1b2与-32π2x3y5的次数相等,则(-1)n+1=______.
答案
∵3a2-2ab3-7an-1b2与-32π2x3y5的次数相等,
∴n-1+2=8,即n+1=8.
∴(-1)n+1=1.
已知3a2-2ab3-7an-1b2与-32π2x3y5的次数相等,则(-1)n+1=______.
∵3a2-2ab3-7an-1b2与-32π2x3y5的次数相等,
∴n-1+2=8,即n+1=8.
∴(-1)n+1=1.