问题 解答题
已知实数x,y,z满足
x
y+z
+
y
z+x
+
z
x+y
=1
,求
x2
y+z
+
y2
z+x
+
z2
x+y
的值.
答案

x
y+z
+
y
z+x
+
z
x+y
=1,

x
y+z
=1-(
y
z+x
+
z
x+y
),

y
z+x
=1-(
x
y+z
+
z
x+y
),

z
x+y
=1-(
x
y+z
+
y
z+x
),

x2
y+z
+
y2
z+x
+
z2
x+y
=x•
x
y+z
+y•
y
z+x
+z•
z
x+y

=x•[1-(

y
z+x
+
z
x+y
)]+y•[1-(
x
y+z
+
z
x+y
)]+z•[1-(
x
y+z
+
y
z+x
)]

=x-

xy
z+x
-
xz
x+y
+y-
xy
y+z
-
yz
x+y
+z-
xz
y+z
-
yz
z+x

=x+y+z-

xy+yz
z+x
-
xz+yz
x+y
-
xy+xz
y+z

=x+y+z-y-z-x

=0.

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