问题
解答题
计算:
(1)-an(an+1-an+an-1-2);
(2)x2(x-1)+2x(x2-2x+3).
答案
(1)原式=-a2n+1+a2n-a2n-1+2an;
(2)原式=x3-x2+2x3-4x2+6x=3x3-5x2+6x.
计算:
(1)-an(an+1-an+an-1-2);
(2)x2(x-1)+2x(x2-2x+3).
(1)原式=-a2n+1+a2n-a2n-1+2an;
(2)原式=x3-x2+2x3-4x2+6x=3x3-5x2+6x.