问题 解答题
(1)计算:
2
(2cos45°-sin60°)+
24
4

(2)化简:[
(a+1)(a-2)
a2-4a+4
-
a
a2-2a
a
a-2
答案

(1)

2
(2cos45°-sin60°)+
24
4

=

2
(2•
2
2
-
3
2
)+
2
6
4

=2-

6
2
+
6
2

=2;

(2)[

(a+1)(a-2)
a2-4a+4
-
a
a2-2a
a
a-2

=[

(a+1)(a-2)
(a-2)2
-
a
a(a-2)
]÷
a
a-2

=(

a+1
a-2
-
1
a-2
a-2
a

=

a
a-2
a-2
a

=1.

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