问题
选择题
把一个“12V 6W”的灯泡接入电路中,若通过灯泡的电流是0.3A,则灯泡的实际功率( )
A.等于6W
B.大于6W
C.小于6W
D.无法判断
答案
灯泡的电阻为:
R=
=U2 P
=24Ω,(12V)2 6W
通过它的电流是0.3A时灯泡的实际功率为:
P′=(I′)2R=(0.3A)2×24Ω=2.16W<6W.
故选C.
把一个“12V 6W”的灯泡接入电路中,若通过灯泡的电流是0.3A,则灯泡的实际功率( )
A.等于6W
B.大于6W
C.小于6W
D.无法判断
灯泡的电阻为:
R=
=U2 P
=24Ω,(12V)2 6W
通过它的电流是0.3A时灯泡的实际功率为:
P′=(I′)2R=(0.3A)2×24Ω=2.16W<6W.
故选C.
阅读理解。 | ||
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