问题
解答题
先化简,再求值:(x+1)÷
|
答案
原式=(x+1)•
-(x+1)(x-1) (x+1)2 x-3 x+1
=
-(x+1)(x-1) x+1 x-3 x+1
=(x+1)(x-1)-(x-3) x+1
当x=tan60°-1=
-1时,原式=3
=
(3
-2)-(3
-4)3 3
=3-2
-3
+43 3
=7-3 3 3
.7
-93 3
先化简,再求值:(x+1)÷
|
原式=(x+1)•
-(x+1)(x-1) (x+1)2 x-3 x+1
=
-(x+1)(x-1) x+1 x-3 x+1
=(x+1)(x-1)-(x-3) x+1
当x=tan60°-1=
-1时,原式=3
=
(3
-2)-(3
-4)3 3
=3-2
-3
+43 3
=7-3 3 3
.7
-93 3