问题
解答题
当a=
|
答案
原式=[
-4 (a-1)(a+1)
]÷2 a(a+1) 1 a-1
=
×(a-1)4a-2(a-1) a(a-1)(a+1)
=2(a+1) a(a+1)
=2 a
∵a=
,2
∴原式=
=2 2
.2
当a=
|
原式=[
-4 (a-1)(a+1)
]÷2 a(a+1) 1 a-1
=
×(a-1)4a-2(a-1) a(a-1)(a+1)
=2(a+1) a(a+1)
=2 a
∵a=
,2
∴原式=
=2 2
.2