问题
解答题
先化简,再求值:
|
答案
原式=
-2 x-1
•1 (x+1)(x-1) (x+1)2 x-1
=
-2 x-1
=x+1 (x-1)2 2x-2-x-1 (x-1)2
=x-3 (x-1)2
当x=
+1时,原式=3
.
-23 3
先化简,再求值:
|
原式=
-2 x-1
•1 (x+1)(x-1) (x+1)2 x-1
=
-2 x-1
=x+1 (x-1)2 2x-2-x-1 (x-1)2
=x-3 (x-1)2
当x=
+1时,原式=3
.
-23 3