问题
解答题
已知x=2010,y=2009,求代数式(x-
|
答案
(x-
)÷2xy-y2 x
=x-y x
•x2-2xy+y2 x
=x x-y
•(x-y)2 x
=x-y,x x-y
当x=2010,y=2009时,原式=x-y=2010-2009=1.
已知x=2010,y=2009,求代数式(x-
|
(x-
)÷2xy-y2 x
=x-y x
•x2-2xy+y2 x
=x x-y
•(x-y)2 x
=x-y,x x-y
当x=2010,y=2009时,原式=x-y=2010-2009=1.