问题
解答题
先化简，再求值：(
|
答案
原式=（
+1 x-2
）•1 x+2 (x+2)(x-2) x2
=
•1 x-2
+(x+2)(x-2) x2
•1 x+2 (x+2)(x-2) x2
=
+x+2 x x-2 x
=2x x
=2．
搜题请搜索小程序“爱下问搜题”
先化简，再求值：(
|
原式=（
+1 x-2
）•1 x+2 (x+2)(x-2) x2
=
•1 x-2
+(x+2)(x-2) x2
•1 x+2 (x+2)(x-2) x2
=
+x+2 x x-2 x
=2x x
=2．
