问题
解答题
先化简
|
答案
原式=
÷[-2xy (x+y)(x-y)
-x+y (x+y)(x-y)
]x-y (x+y)(x-y)
=
÷-2xy (x+y)(x-y)
=2y (x+y)(x-y)
•-2xy (x+y)(x-y)
=-x，(x+y)(x-y) 2y
当x=1-
时，原式=-（1-2
）=2
-1．2
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先化简
|
原式=
÷[-2xy (x+y)(x-y)
-x+y (x+y)(x-y)
]x-y (x+y)(x-y)
=
÷-2xy (x+y)(x-y)
=2y (x+y)(x-y)
•-2xy (x+y)(x-y)
=-x，(x+y)(x-y) 2y
当x=1-
时，原式=-（1-2
）=2
-1．2