问题
解答题
计算:(1)
|
答案
(1)
÷x+2 x2-6x+9
×1 3-x x-3 x+2
=
×(3-x)×x+2 (x-3)2 x-3 x+2
=-1;
(2)(
-x+1)÷x2-1 x2-2x+1 x x-1
=[
-(x-1)(x+1) (x-1)2
]×(x-1)2 x-1 x-1 x
=
×-x2+3x x-1 x-1 x
=-x+3.
计算:(1)
|
(1)
÷x+2 x2-6x+9
×1 3-x x-3 x+2
=
×(3-x)×x+2 (x-3)2 x-3 x+2
=-1;
(2)(
-x+1)÷x2-1 x2-2x+1 x x-1
=[
-(x-1)(x+1) (x-1)2
]×(x-1)2 x-1 x-1 x
=
×-x2+3x x-1 x-1 x
=-x+3.