问题
解答题
先化简,再求值: ①
②(
|
答案
①原式=
-2 x+1
•1 (x+1)(x-1) (x-1)2 x
=
-2 x+1 x-1 x(x+1)
=2x-(x-1) x(x+1)
=x+1 x(x+1)
=
,1 x
当x=5时,原式=
;1 5
②原式=[
-(x-1)(x+1) x(x+1)
]•x(x-2) x(x+1) (x+1)2 x(2x-1)
=
•(x-1)(x+1)-x(x-2) x(x+1) (x+1)2 x(2x-1)
=
•2x-1 x(x+1) (x+1)2 x(2x-1)
=
,x+1 x2
当x2-x-1=0时,x2=x+1,
则原式=1.