问题 解答题
(1)已知x=2,y=5.求代数式:1-
x-y
x-2y
÷
x2-y2
x2-4xy+4y2
的值.
(2)化简求值:(
x+2
x-2
+
4
x2-4x+4
x
x-2
,其中x=-
1
2
答案

(1)原式=1-

x-y
x-2y
(x-2y)2
(x-y)(x+y)

=1-

x-2y
x+y

=

x+y-x+2y
x+y

=

3y
x+y

当x=2,y=5时,原式=

3×5
2+5
=
15
7

(2)原式=

(x+2)(x-2)+4
(x-2)2
x-2
x

=

x2
(x-2)2
x-2
x

=

x
x-2

当x=-

1
2
时,原式=
-
1
2
-
1
2
-2
=
1
5

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