问题 解答题
计算:
(1)
x+1
x
•(
2x
x+1
)2-(
1
x-1
-
1
x+1
)

(2)
5x+3y
x2-y2
-
2x
x2-y2
答案

(1)原式=

x+1
x
4x2
(x+1)2
-
x+1-x+1
(x+1)(x-1)

=

4x
x+1
-
2
(x+1)(x-1)

=

4x2-4x-2
(x+1)(x-1)

(2)原式=

5x+3y-2x
x2-y2

=

3(x+y)
(x+y)(x-y)

=

3
x-y

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