问题
解答题
先化简(
|
答案
原式=
-x(x+1) (x-1)(x+1)
,x-1 (x-1)(x+1)
=
,x2+x-x+1 (x-1)(x+1)
=
,x2+1 x2-1
∴(
-x x-1
)÷1 x+1
=1 x2-1
•x2+1 x2-1
=x2+1.x2-1 1
取x=0代入上式得,
=02+1
=1.
先化简(
|
原式=
-x(x+1) (x-1)(x+1)
,x-1 (x-1)(x+1)
=
,x2+x-x+1 (x-1)(x+1)
=
,x2+1 x2-1
∴(
-x x-1
)÷1 x+1
=1 x2-1
•x2+1 x2-1
=x2+1.x2-1 1
取x=0代入上式得,
=02+1
=1.