问题
解答题
化简求值 (1)(1+
|
答案
(1)原式=
÷x-1+1 x-1 x-1-1 x-1
=
•x x-1 x-1 x-2
=
.x x-2
当x=-
时,原式=1 2
.1 5
(2)原式=
÷-(x-1) (x+2)(x-1)
=-(x-2)(x+2)+3 x+2
•1 x+2
=-x+2 x2-1
.1 x2-1
当x=
时,原式=1 2
.4 3
化简求值 (1)(1+
|
(1)原式=
÷x-1+1 x-1 x-1-1 x-1
=
•x x-1 x-1 x-2
=
.x x-2
当x=-
时,原式=1 2
.1 5
(2)原式=
÷-(x-1) (x+2)(x-1)
=-(x-2)(x+2)+3 x+2
•1 x+2
=-x+2 x2-1
.1 x2-1
当x=
时,原式=1 2
.4 3