问题 解答题
计算:
(1)(-12a2b2c)•(-
1
4
abc22=______;
(2)(3a2b-4ab2-5ab-1)•(-2ab2)=______.
答案

(1)(-12a2b2c)•(-

1
4
abc22

=(-12a2b2c)•

1
16
a2b2c4

=-

3
4
a4b4c5

故答案为:-

3
4
a4b4c5

(2)(3a2b-4ab2-5ab-1)•(-2ab2),

=3a2b•(-2ab2)-4ab2•(-2ab2)-5ab•(-2ab2)-1•(-2ab2),

=-6a3b3+8a2b4+10a2b3+2ab2

故答案为:-6a3b3+8a2b4+10a2b3+2ab2

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