问题
解答题
先化简,再求值:1-
|
答案
原式=1-
a-1 |
a |
a2-1 |
a(a+2) |
=1-
a-1 |
a |
a(a+2) |
(a+1)(a-1) |
=1-
a+2 |
a+1 |
=
a+1-(a+2) |
a+1 |
=
a+1-a-2 |
a+1 |
=-
1 |
a+1 |
原式=-
1 | ||
|
1 | ||
|
| ||
2 |
先化简,再求值:1-
|
原式=1-
a-1 |
a |
a2-1 |
a(a+2) |
=1-
a-1 |
a |
a(a+2) |
(a+1)(a-1) |
=1-
a+2 |
a+1 |
=
a+1-(a+2) |
a+1 |
=
a+1-a-2 |
a+1 |
=-
1 |
a+1 |
原式=-
1 | ||
|
1 | ||
|
| ||
2 |