问题
解答题
先化简,再求值:1-
|
答案
原式=1-
÷a-1 a a2-1 a(a+2)
=1-
•a-1 a a(a+2) (a+1)(a-1)
=1-a+2 a+1
=a+1-(a+2) a+1
=a+1-a-2 a+1
=-
,1 a+1
原式=-
=-1
-1+12
=-1 2
.2 2
先化简,再求值:1-
|
原式=1-
÷a-1 a a2-1 a(a+2)
=1-
•a-1 a a(a+2) (a+1)(a-1)
=1-a+2 a+1
=a+1-(a+2) a+1
=a+1-a-2 a+1
=-
,1 a+1
原式=-
=-1
-1+12
=-1 2
.2 2