问题
解答题
计算. (1)
(2)
|
答案
(1)原式=
•2(x-3) (x-2)2
•1 x+3 (x+3)2 3-x
=-
;2(x+3) (x-2)2
(2)原式=
-2 a+1
•a-2 (a-1)(a+1) (a-1)2 a(a-2)
=
-2 a+1 a-1 a+1
=
.3-a a+1
计算. (1)
(2)
|
(1)原式=
•2(x-3) (x-2)2
•1 x+3 (x+3)2 3-x
=-
;2(x+3) (x-2)2
(2)原式=
-2 a+1
•a-2 (a-1)(a+1) (a-1)2 a(a-2)
=
-2 a+1 a-1 a+1
=
.3-a a+1