问题
解答题
化简下列各式: (1)
(2)(-
(3)
(4)(
|
答案
(1)原式=2a-a-2 (a+2)(a-2)
=
;1 a+2
(2)原式=a2b3;
(3)原式=
÷3-x 2(x-2) x2-9 x-2
=
×3-x 2(x-2) x-2 (x+3)(x-3)
=-
;1 2(x+3)
(4)原式=
×x-2y x-y
×xy x-2y xy x+y
=
.x2y2 x2-y2
故答案为
、a2b3、-1 a+2
、1 2(x+3)
.x2y2 x2-y2